Question
A man divides his savings among his son, daughter and wife in such a way that the ratio of daughter's share to wife's share, as well as wife's share to son's share is 5 : 3. If the daughter gets βΉ56,000 more than the son, then find the total savings of the person (in βΉ).
Solution
ATQ,
Given: Daughter : Wife = 5:3 Wife : Son = 5:3 Daughter gets βΉ56,000 more than Son Common ratio β Daughter : Wife : Son = 25x : 15x : 9x Difference = 25x β 9x = 16x = 56,000 β x = 56,000 Γ· 16 = βΉ3,500 Total = 25x + 15x + 9x = 49x β 49 Γ 3,500 = βΉ1,71,500
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