Question
Two cyclists travel from X to Y at speeds of 18 km/hr
and 24 km/hr. If one of them takes 15 minutes less time than the other to reach the destination, then find the distance (in km) between X and Y.Solution
Given: Speedā = 18 km/h Speedā = 24 km/h Time difference = 15 min = 1/4 hr Let distance = d km Equation: d/18 ā d/24 = 1/4 LCM of 18 and 24 = 72 (4d ā 3d)/72 = 1/4 d/72 = 1/4 d = 72 Ć 1/4 = 18
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