Question
Find the area of a square, one of whose diagonals is 4.8
m long.Solution
Let the side of the square be s In a square, the diagonal d is given by: d = s√2 d = 4.8, s = 3.8/√2 = 2.4√2 Area of the square = s2 = (2.4√2)2 = 11.52 sq m
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