Question
In triangles ABC and DEF, AB = FD and ∠A = ∠D. The
two triangles are congruent by SAS criterion if:ÂSolution
Side: AB = FD (one pair of sides are equal) Angle: ∠A = ∠D (one pair of angles are equal) To satisfy the SAS criterion, we need one more pair of sides that are opposite the given angle. Since the given angle is ∠A=∠D, we must find the side opposite to these angles: In â–³ABC, the side opposite to ∠A is AC. In â–³DEF, the side opposite to ∠D is DE. Therefore, AC = DEÂ
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