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      Question

      Which of the following statements accurately describes

      the relationship between the incorrect numbers in Series I and Series II? Series I: 17, 45, 141, 420, 1257, 3765 Series II: 4, 6, 15, 60, 275, 1644 I. The incorrect number in Series I is divisible by the incorrect number in Series II. II. The sum of the incorrect numbers is a multiple of 15. III. If 39 is subtracted from the incorrect number in Series II and the result is squared, it exceeds the incorrect number in Series I. IV. The difference between the incorrect numbers is a multiple of 13.
      A Only I and II Correct Answer Incorrect Answer
      B Only II and III Correct Answer Incorrect Answer
      C Only I, III and IV Correct Answer Incorrect Answer
      D Only IV Correct Answer Incorrect Answer
      E All I, II, III and IV Correct Answer Incorrect Answer

      Solution

      ATQ, Series I: 17, 45, 141, 420, 1257, 3765 Pattern: 17 Γ— 3 βˆ’ 3 = 48 48 Γ— 3 βˆ’ 3 = 141 141 Γ— 3 βˆ’ 3 = 420 420 Γ— 3 βˆ’ 3 = 1257 1257 Γ— 3 βˆ’ 3 = 3768 So, 45 is incorrect. Correct term should be 48. Incorrect number in Series I = 45 Series II: 4, 6, 15, 60, 275, 1644 Pattern: 4 β†’ 6 = 2 Γ— (4 βˆ’ 1) 6 β†’ 15 = 3 Γ— (6 βˆ’ 1) 15 β†’ 56 = 4 Γ— (15 βˆ’ 1) 56 β†’ 275 = 5 Γ— (56 βˆ’ 1) 275 β†’ 1644 = 6 Γ— (275 βˆ’ 1) So, 60 is incorrect. Correct term should be 56. Incorrect number in Series II = 60 Now check the statements: I. 45 is divisible by 60 False II. 45 + 60 = 105, which is a multiple of 15 True III. (60 βˆ’ 39)Β² = 21Β² = 441, which is greater than 45 True IV. 60 βˆ’ 45 = 15, which is not a multiple of 13 False Correct Answer: Statements II and III are correct.

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