Question
Which of the following statements accurately describes
the relationship between the incorrect numbers in Series I and Series II? Series I: 17, 45, 141, 420, 1257, 3765 Series II: 4, 6, 15, 60, 275, 1644 I. The incorrect number in Series I is divisible by the incorrect number in Series II. II. The sum of the incorrect numbers is a multiple of 15. III. If 39 is subtracted from the incorrect number in Series II and the result is squared, it exceeds the incorrect number in Series I. IV. The difference between the incorrect numbers is a multiple of 13.Solution
ATQ, Series I, (17 - 2) × 3 = 45 (45 + 2) × 3 = 141 (141 - 2) × 3 = 417 (417 + 2) × 3 = 1257 (1257 - 2) × 3 = 3765 Wrong Number = 420 Series II, (4 - 1) × 2 = 6 (6 - 1) × 3 = 15 (15 - 1) × 4 = 56 (56 - 1) × 5 = 275 (275 - 1) × 6 = 1644 Wrong Number = 60 I) 420/60 = 7 (Correct) II) (420 + 60)/15 = 480/15 = 32 (Correct) III) (60 - 39)2 = 212 = 441 > 420 (Correct) IV) (420 - 60)/13 = 360/13 = 27 + 9/13 (Incorrect) Hence, Only I, II and III are true.
More Previous year papers Questions
- Determine the final value of this expression:
(1/5) of {5⁴ - 24 × 14 + 12 × 18 - 10.5 of 10²} 3% of 842 ÷ 2% of 421 = ?
√225 + 27 × 10 + ? = 320
- Determine the value of ‘p’ if p = √529 + √1444
45 % of 180 + √144 * 8 = ?2 + 70 % of 80
Determine the value of 'p' in following expression:
720 ÷ 9 + 640 ÷ 16 - p = √121 X 5 + 6²- 7?2 = √20.25 × 10 + √16 + 32
- What will come in place of the question mark (?) in the following questions?
(2⁴ + 6²) ÷ 2 = ? 18(1/3) + 9(2/3) – 10(1/3) = 1(2/3) + ?
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