Question
If 1306x is divisible by 9, then find the value of
√(x2 – 28).Solution
If 1306x is divisible by 9, then sum of the digit must be divisible by 9
So, 1 + 3 + 0 + 6 + x = (10 + x) = 9n (where n is a positive integer)
So, (10 + x) = 18
So, x = 18 – 10 = 8
√(x2 – 28) = √(64 – 28) = √36 = 6
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