Question
Two circles of same radius 6 cm, intersect each other at P and Q. If PQ = 10cm, then what is the distance between the centers of the two circles?
According to the given picture, O₁ and O2 be the centres of the two circles, The line joining the centers 01, 02 bisect PQ at R So, the triangle PRO₁ is a right-angle triangle, right angle at From Pythagoras theorem, O₁R = √ (62-52) OR = √ 11 Now, distance between O₁ and O2 is 2 x O₁R = 2√11 cmMore Previous year papers Questions
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