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    Question

    Two cylinders have the same volume, but the radius of

    the base of the second cylinder is 20% less than the radius of the base of the first. How much greater should the height of the second cylinder be in comparison to the height of the first?
    A 55.25% Correct Answer Incorrect Answer
    B 56.25% Correct Answer Incorrect Answer
    C 56.75% Correct Answer Incorrect Answer
    D 55.75% Correct Answer Incorrect Answer

    Solution

    Let the radius of the first cylinder be R. Now, the radius of the base of the second cylinder =R-Rx 20% =R-0.2R =0.8R Let height of the first and second cylinder be H ₁ and H ₂ respectively. According to the question, π x R2 x H ₁ = 1 x (0.8R)2 x H2 R2 x H ₁ = 0.64R2 x H2 H ₁ = 0.64H2 Now, % greater = (H2- 0.64H2)/0.64H2 × 100% =0.36/0.64 × 100% =56.25% 56.25% greater the height of the second cylinder should be in comparison to the height of the first.

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