Question
If cos θ + sec θ = √3, then the value of cos³ θ+
sec³ θ is:Solution
cos θ + sec θ = √3 cos³ θ+ sec³ θ = (cos θ + sec θ)3 - 3 ×cos θ × sec θ (cos θ + sec θ) = (√3)3 - 3× cos θ×1/ cos θ (√3) =3√3 -3√3 =0
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