The volume of three containers are in the ratio of 4 : 5 : 6. They are full of mixture of petrol to kerosene in the ratios of (3:1), (3:2) and (5:1), respectively. The entire quantities of these mixtures from of these three containers are poured into a fourth container. The ratio of petrol to kerosene in the fourth container is ______

Let the volume of containers be 4 liters, 5 liters, and 6 liters. For Container I, ⇒ Petrol = (3/4 × 4) = 3 liters ⇒ Kerosene = (1/4 × 4) = 1 liters For Container II, ⇒ Petrol = (3/5 × 5) = 3 liters ⇒ Kerosene = (2/5 × 5) = 2 liters For Container III, ⇒ Petrol = (5/6 × 6) = 5 liters ⇒ Kerosene = (1/6 × 6) = 1 liters The required ratio for the IV container, Total petrol : Total kerosene ⇒ (3 + 3 + 5) : (1 + 2 + 1) ⇒ 11 : 4 ∴The ratio of petrol to kerosene in the fourth container is 11 : 4.