Question
A dealer sells two machines at the rate of Rs. 12000
per machine. On one he earns a profit of 20 percent and on the other he loses 20 percent. What is his profit/loss percentage in the whole transaction?Solution
Given: SP of each machine = Rs. 12000 CP of first machine = 12000 × 100/120 = Rs. 10000 CP of second machine = 12000 × 100/80 = Rs. 15000 Total SP = Rs. 24000 Total CP = Rs. 25000 Therefore, Loss% = (25000 – 24000)/25000 × 100 = 4%
More Previous year papers Questions
1885 ÷ 64.98 + 7.29 + ? = 69.09
212 + 14 × 23 – 28 × 15 = ? Â
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
567-4824 ÷ 134 =? × 9
Determine the value of 'p' in the expression.
28 ÷ 22p + 1 = 43Â
What will come in place of (?) in the given expression.
(15) ² - (13) ² = ?? = 6.25% of 240 + 25 2 + 17 2 – 16 × 17
35% of 840 + 162 = ? – 25% × 300
(7/5) × (3/4) × (5/9) × (6/7) × 3112 = ?
1024 ÷ 16 + 800 ÷ √64 + ? = 200 * 2
