Question
A dealer sells two machines at the rate of Rs. 12000
per machine. On one he earns a profit of 20 percent and on the other he loses 20 percent. What is his profit/loss percentage in the whole transaction?Solution
Given: SP of each machine = Rs. 12000 CP of first machine = 12000 × 100/120 = Rs. 10000 CP of second machine = 12000 × 100/80 = Rs. 15000 Total SP = Rs. 24000 Total CP = Rs. 25000 Therefore, Loss% = (25000 – 24000)/25000 × 100 = 4%
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Conclusion
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II: R ≥ E
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