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Sin x + Sin2x = 1 Sinx=1-Sin2x =cos2x Sinx =cos2x ...(1) Sin x + Sin2x = 1 ...(2) both sides squaring. (Sin x + Sin2x)2 = (1)2 sin2x+sin4 x+2.sinx.sin2x =1 sin2x+sin4x+2.sin3 x =1 now put the value of sinx from Eq (1).. Cos8x + 2cos6x + Cos4x =1
? + 539.76 ÷ 5.4 × 94.80 = 9829.54
√3601 × √(224) ÷ √102 = ?
30.11% of 149.99 + √ 143.97 ÷ 12.02 = ?
49.99% of 539.99 + 263.98% of 49.99 = ?% of 1608.01
456.9 + 328.10 - 122.98 = ? + 232.11
12.99 × 9.99 + ? × 7 + 240.001 = 21.012
20.11% of 119.99 + √80.97 ÷ 3.02 = ?
14.96% of 120.03 - 107.99 + 88.93% of 199.87 = ?