Question
A bag contains rupee, 50 paise, 25 paise and 10 paise
coins in the proportion 1:3:5:7. If the total amount is ` 22.25, find the number of coins of each kind:Solution
Let, x be the common multiple. 1 rupee coins = x 50 paise coins = 3x 25 paise coins = 5x 10 paise coins = 7x According to the question, => (100 × x) + (50 × 3x) + (25 × 5x) + (10 × 7x) = 22.25 × 100 => 100x + 150x + 125x + 70x = 2225 => 445x = 2225 => x = 5 Therefore, the number of, 1 rupee coins = 5 50 paise coins = 15 25 paise coins = 25 10 paise coins = 35
I. 6 y² + 11 y – 7= 0
II. 21 x² + 5 x – 6 = 0
- For what value of a does the quadratic equation x² + ax + 81 = 0 have real and identical roots?
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
I. 2x² - 15x  + 13 = 0
II. 3y² - 6y + 3 = 0
I. 2x² - 7x + 3 = 0
II. 8y² - 14y + 5 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x2 + 6√7x - 315 = 0    Â
E...
I. 35x² - 51x + 18 = 0
II. 30y² + 17y – 21 = 0
I. 195x² - 46x - 21 = 0
II. 209y² + 7y - 12 = 0
I. 2y2 - 37y + 143 = 0
II. 2x2 + 15x – 143 = 0
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
