Question
A boat takes half time in moving a certain distance
downstream than upstream. What is the ratio between rate in still water and rate of current ?Solution
Let the speed of a boat in still water = ukmph And, speed of current = vkmph Rate downstream = (u+v) kmph Rate upstream =(u−v)kmph Let the distance covered in each case be x km. Then, (2x/u+v) = (x/u−v) 2(u−v) = u+v u = 3v (u/v) = 3:1 Therefore, Required ratio = 3:1
7, 14, 42, 210, 1470, ?
A sequence {Vₙ} is defined for n ≥ 1 by:
I) For every n ≥ 3: Vₙ = 2Vₙ₋₁ − Vₙ₋₂ + 4
It is known that - V₃ = 22 and ...
12, 20, 36, ?, 132, 260
If 6 4 x 5.75 9,
Then, (x²-1) = ?
...12 13 30 �...
112 162 199 ? 242 252
...21 11.5 13 ? 45.5 116.75
...171, 173, 183, 213 , ‘?’, 411, 633.
114 106 102 100 99 ?
...Choose the correct alternative
21: 3 ∷ 574: ?