Question
A boat takes half time in moving a certain distance
downstream than upstream. What is the ratio between rate in still water and rate of current ?Solution
Let the speed of a boat in still water = ukmph And, speed of current = vkmph Rate downstream = (u+v) kmph Rate upstream =(u−v)kmph Let the distance covered in each case be x km. Then, (2x/u+v) = (x/u−v) 2(u−v) = u+v u = 3v (u/v) = 3:1 Therefore, Required ratio = 3:1
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1885 ÷ 64.98 + 7.29 + ? = 69.09
212 + 14 × 23 – 28 × 15 = ? Â
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
567-4824 ÷ 134 =? × 9
Determine the value of 'p' in the expression.
28 ÷ 22p + 1 = 43Â
What will come in place of (?) in the given expression.
(15) ² - (13) ² = ?? = 6.25% of 240 + 25 2 + 17 2 – 16 × 17
35% of 840 + 162 = ? – 25% × 300
(7/5) × (3/4) × (5/9) × (6/7) × 3112 = ?
1024 ÷ 16 + 800 ÷ √64 + ? = 200 * 2
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