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ATQ, Consider 'x' cm as the smaller parallel side So the longer parallel side can be written as (x + 12) cm It is given that height = 60cm Area = 1380 cm2 We know that Area of trapezium =(1/2) × sum of parallel sides × height By substituting the values 1380 = (1/2) × (x + x + 12) × 60 On further calculation 1380 = 30 × (2x+12) By division 2x + 12 = 46 So we get 2x = 46 – 12 By subtraction 2x = 34 By division x = 17 cm So we get x + 12 = 17 + 12 = 29cm Therefore, the length of each of the parallel sides is 12 cm and 29 cm.
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