The difference between the length of two parallel sides of a trapezium is 12
cm. The perpendicular distance between these two parallel sides is 60
cm. If the area of the trapezium is 1380 cm2, then find the length of each of the parallel sides (in cm).

ATQ, Consider 'x' cm as the smaller parallel side So the longer parallel side can be written as (x + 12) cm It is given that height = 60cm Area = 1380 cm² We know that Area of trapezium =(1/2) × sum of parallel sides × height By substituting the values 1380 = (1/2) × (x + x + 12) × 60 On further calculation 1380 = 30 × (2x+12) By division 2x + 12 = 46 So we get 2x = 46 – 12 By subtraction 2x = 34 By division x = 17 cm So we get x + 12 = 17 + 12 = 29cm Therefore, the length of each of the parallel sides is 12 cm and 29 cm.