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ATQ, P(A) = 3/7, P(B) = 5/9, P(C) = 1/5 All students solves the problem independently, so if at least one of them solves the problem then the problem is considered solved. Probability that the problem is unsolved = [1 – P(A)][1 – P(B)][1 – P(C)] = (64/315) The probability that the problem will be solved = 1 – Probability that the problem is unsolved = (1- (64/315)) = (251/315)
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