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According to the question ∠DBC = 29° ∠BDC = 90° [Angle in a semicircle is 90°] We know that sum of all the sides of triangles is 180° ⇒ ∠DBC + ∠BDC + ∠BCD = 180° ⇒ 29° + 90° + ∠BCD = 180° ⇒ 119° + ∠BCD = 180° ⇒ ∠BCD = (180° – 119°) ⇒ ∠BCD = 61° Now, We know that, the opposite angles in a cyclic quadrilateral is 180° So, ⇒ ∠BAD + ∠BCD = 180° ⇒ ∠BAD + 61° = 180° ⇒ ∠BAD = (180° – 61°) ⇒ ∠BAD = 119°
A piece of paper is folded and cut as shown below in the question figures from the given answer figures, indicates how it will appear when opened?
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Option figures:
Which figure is different from the rest?
Select a suitable figure from the Answer Figures that would replace the question mark (?) from question figure.
Select the figure that can replace the question mark (?) in the following series.
Select the option figure in which the given figure is embedded(rotation is NOT allowed).
How many triangles are present in the following figure?
Three of the following four figure pairs are alike in a certain way and thus form a group. Which is the one that does not belong to that group?
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