Question
A and B together can do a piece of work in 20 days. B
and C together can do the same of work in 25 days. C and A together can do the same work in 15 days. In how many days A alone can do the same work?Solution
Work done by A & B together = 20 Work done by B & C together = 25 Work done by C & A together = 15 Total work done A, B & C = LCM of 20, 25 & 15 = 300 units Efficiency of A & B together = 300/20 = 15 Efficiency of  B & C together = 300/25 = 12 Efficiency of  C & A together = 300/15 = 20 ⇒ 2(A + B + C) = 47 (Efficiency) ⇒ A + B + C = 23.5   ---- (1) ⇒ B + C = 12   ---- (2) From (1) and (2) ⇒ A = 11.5 ⇒ A alone can do the same work = total work/efficiency of A ⇒ A alone can do the same work = 300/11.5 = 600/23 days ∴ A alone can do the same work in 600/23 days
 Which of the following risks is borne by the entrepreneur:
If a bank employee notices a senior manager manipulating loan records and reports it, this is called:
"Conflict of Commitment" refers to a situation where:
The maximum penalty that can be imposed on a Public Information Officer (PIO) for violating the RTI Act is:
In public service, "Accountability" implies being answerable to:
Within how many days must a "First Appeal" be filed if dissatisfied?
The idea and actions that explain how an entrepreneur will make his/her venture profitable and impactful is commonly referred to asÂ
Which schedule of the RTI Act lists exempted security organizations?
In the context of public service, "Impartiality" most closely aligns with:
"Post-retirement employment" of government officials in private companies they previously regulated raises concerns about:
Relevant for Exams:
