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      Question

      If a2sec2x –

      b2tan2x = c2 then the value of sec2x + tan2x is equal to (assume b2 ≠ a2)
      A (b^2 – a^2 + 2c^2 / b^2 + a^2) Correct Answer Incorrect Answer
      B (b^2 + a^2 – 2c^2 / b^2 – a^2) Correct Answer Incorrect Answer
      C (b^2 – a^2 – 2c^2 / b^2 + a^2) Correct Answer Incorrect Answer
      D (b^2 – a^2 / b^2 + a^2 + 2c^2) Correct Answer Incorrect Answer

      Solution

      The correct answer is B

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