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    Question

    If a2sec2x –

    b2tan2x = c2 then the value of sec2x + tan2x is equal to (assume b2 ≠ a2)
    A (b^2 – a^2 + 2c^2 / b^2 + a^2) Correct Answer Incorrect Answer
    B (b^2 + a^2 – 2c^2 / b^2 – a^2) Correct Answer Incorrect Answer
    C (b^2 – a^2 – 2c^2 / b^2 + a^2) Correct Answer Incorrect Answer
    D (b^2 – a^2 / b^2 + a^2 + 2c^2) Correct Answer Incorrect Answer

    Solution

    The correct answer is B

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