Question
What is the compound interest on a sum of ₹19,500
invested for 1(2/5) years at 10% p.a., interest compounded annually?Solution
Interest rate for 2/5 years = 10 × (2/5) = 4% Now, A = 19500(1 + 10/100)1 × (1 + 4/100)2/5 A = 19500(1 + 10/100) × (1 + 4/100) A = 19500(1 + 1/10) × (1 + 1/25) A = 19500(11/10) × (26/25) A = 22308 So, interest of the given years = 22308 - 19500 Rs. 2808
(500 × 6 ÷ 10) - (√256 + 8) = ?
22% of 400 + √ ? = 34% of 800 - 25% of 400
(2/5)(32% of 4500 – 440) = ? × 8
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
What will come in the place of question mark (?) in the given expression?
96 ÷ (9 - 6.6) + 17.5 X 6 = ? ÷ 8
13 X ? = 85 X 4 + √81 + 2
45% of 360 - 160 + ? = √324
((67)32 × (67)-18 / ? = (67)⁸
4567.89 - 567.89 - 678.89 = ?
82.3 × 644.7 × 723.4 × 815.85 = 72?