Question
Pipe 'A' is 5 times as efficient as pipe 'B'. Pipe 'C',
which is one-fifth as efficient as pipe 'B', can fill a tank alone in 25 hours. Find difference between time taken by pipe 'C' to fill 60% of the tank and time taken (in minutes) by pipe 'A' to fill the tank completely.Solution
Let the efficiency of pipe 'C' be 'x' litres/hour.
So, total capacity of the tank = '25x' litres.
Efficiency of pipe 'A' = x × 5 × 5 = '25x' litres/hour
So, time taken by pipe 'A' to fill the tank = 25x / 25x = 1 hour
And, time taken by pipe 'C' to fill 60% of the tank = (25x × 0.6) / x = 15 hours
So, required difference = 15 - 1 = 14 hours = 14 × 60 = 840 minutes
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