Question
Pipe A alone and pipe C alone can fill the empty tank in
50% less time and 25% less time respectively than the time taken by pipe B to empty the full tank. If the time taken by pipe B alone to empty the full tank is 60 hours, then in how many hours would the tank be 126 litres filled if the pipes A, B and C are opened together?Solution
Time taken by pipe A alone to fill the empty tank = 60 × 0.50 = 30 hours
Time taken by pipe C alone to fill the empty tank = 60 × 0.75 = 45 hours
Let the capacity of the tank = 180 litres (LCM of 30, 45 and 60)
Quantity of water filled by pipe A alone in one hour = 180 / 30 = 6 litres
Quantity of water filled by pipe C alone in one hour = 180 / 45 = 4 litres
Quantity of water taken out by pipe B alone in one hour = 180 / 60 = 3 litres
So the time taken to fill 126 litres of the tank = 126 / (6 + 4 – 3) = 126 / 7 = 18 hours
Find out which of the figures (1), (2), (3) and (4) can be formed from the pieces given in figure (X) .
From the given answer figures, Select the one in which the question is hidden/embedded.
Find out the alternative figure which contains figure (X) as its part.
Select the option in which the given figure is embedded.
Select the option figure which is embedded in the given figure. (Rotation is NOT allowed)
Select the option in which the given figure is embedded (rotation is not allowed)
Select the option figure which is embedded in the given figure. (Rotation is not allowed).
Relevant for Exams:
