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      Question

      Pipe A can fill a tank in 10 hours, whereas pipe B can

      empty the same tank in 12 hours. If the two pipes are operated alternately for one hour each, starting with pipe A, how much time will it take to completely fill the tank?
      A 109 hrs Correct Answer Incorrect Answer
      B 112 hrs Correct Answer Incorrect Answer
      C 124 hrs Correct Answer Incorrect Answer
      D None of the above Correct Answer Incorrect Answer

      Solution

      Let the total capacity of the tank be 60 units

      Efficiency of pipe ‘A’ = 60/10 = 6 units/hour

      Efficiency of pipe ‘B’ = 60/12 = 5 units/hour

      Amount of tank filled in 2 hours = 6 – 5 = 1 units

      Therefore, amount of tank filled in (2 × 54) hours = 54 units

      Therefore, remaining six unit will be filled in 6/6 = 1 hour

      Total time taken = 2 × 54 + 1 = 109 hours

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