Question
Pipes A, B, and C are connected to a tank. Pipe A can fill the empty tank in 48 minutes, and Pipe B can do the same in 80 minutes. On the other hand, Pipe C is an outlet pipe that can empty the full tank in 96 minutes. If all three pipes are opened simultaneously, how long will it take to fill the tank completely?
Solution
Let the capacity of tank be 480 litres (LCM of 48, 80 and 96) . Efficiency of 'A' = (480/48) = 10 litres/minute Efficiency of 'B' = (480/80) = 6 litres/minute Efficiency of 'C' = (480/96) = - 5 litres/minute Therefore, required time = 480 ÷ (10 + 6 - 5) = (480/11) = 43(7/11) mins
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