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Start learning 50% faster. Sign in nowTotal time taken by outlet pipe to empty the tank 'A' = 10 X (100/40) = 25 minutes Let the capacity of tank 'A' be 100 units (L.C.M. of 20 minutes and 25 minutes) Total efficiency of two inlet pipes = (100/20) = 5 units/minute Efficiency of one inlet pipe = 2.5 units/minute Efficiency of outlet pipe = (100/25) = - 4 units/minute Combined efficiency of one inlet and one outlet pipe = 2.5 - 4 = - 1.5 (' - ' sign denotes efficiency of outlet pipe is more than the inlet pipe) Capacity of tank 'B' = (100 X 3) = 300 units Required time = (300/1.5) = 200 minutes
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...16, 24, ?, 64, 104, 168, 272
25 25 37.5 ? 328.125 1804.6875
155, 157, 160, ?, 172, 183
124, 147, 176, 207, 244, ?
5 6 14 45 ? 925
...5, 18, 39, 68, 105, ?
31, 60, 118, 234, 466, ?
What will be the value of 'R + S' in the series: 'Q', 'R', 60, 'S', 240, 'P + 6Q'
8 24 48 144 288 ?
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