Pipe 'X' is capable of emptying a tank in 15 hours. When Pipe 'Y', which adds 2.4 liters of water per hour, is also used, it takes 25 hours to empty the tank. Determine the tank's total capacity.
ATQ, We can say that time taken by pipe ‘Y’ to fill the tank = ‘h’ hours Then, capacity of tank = 2.4h units Therefore, Efficiency of pipe ‘X’ = 2.4h/15 = 0.16h units/hr Efficiency of pipes (X + Y) = 2.4h/25 = 0.096h units/hour Therefore, efficiency of pipe ‘Y’ = -0.096h – (-0.16h) = 0.064h units/hour So, 0.064h = 2.4 h = 37.5 Total capacity of the tank = 37.5 × 2.4 = 90 litres
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