Question
Tap A can fill a tank in 12 hours. Tap B can fill 12.5%
part of the same tank in 2 hours, whereas Tap C can alone empty a tank in ‘x’ hours. 5/8 part of the tank is filled in 6 hours, when all three taps are opened together. How much time (in hours) will Tap A and C together will take to fill 25% part of the tank?Solution
Tap A alone can fill the tank in = 12 hours. Tap B alone can fill the tank in = (8/1) × 2 = 16 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 6 × (8/5) = 48/5 Taking LCM of 12, 16 and 48/5 = 48 Efficiency of Tap A = 4 Efficiency of Tap B = 3 Efficiency of Taps (A + B +C) = 5 Efficiency of Taps (A +C) = 5 – 3 = 2 Tap A and C together take to fill 25% part of the tank in, => (25/100) × (48/2) = 6 hours
?% of 320 = 40% of 40 × 5
{(481 + 426) 2 - 4 × 481 × 426} = ?
- What will come in place of the question mark (?) in the following questions?
(? × 3)2 - 85 = 115 × 5 + 69
What will come in the place of question mark (?) in the given expression?
? X √36 - 184 = 62 X 4
Solve the following equation.
143 + 14.3 + 1.43 + 0.143 + 0.0143 =?
If A = 0.84181818... then what will be the difference between the numerator and denominator of the lowest fraction form of A?
18% of 200 - 16% of 150 = ?
625 × (?% ÷ 125) = 250% of 10
36 × 15 + 20% 1250 = ? + 296
