Question
Tap A can fill a tank in 12 hours. Tap B can fill 12.5%
part of the same tank in 2 hours, whereas Tap C can alone empty a tank in ‘x’ hours. 5/8 part of the tank is filled in 6 hours, when all three taps are opened together. How much time (in hours) will Tap A and C together will take to fill 25% part of the tank?Solution
 Tap A alone can fill the tank in = 12 hours. Tap B alone can fill the tank in = (8/1) × 2 = 16 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 6 × (8/5) = 48/5 Taking LCM of 12, 16 and 48/5 = 48 Efficiency of Tap A = 4 Efficiency of Tap B = 3 Efficiency of Taps (A + B +C) = 5 Efficiency of Taps (A +C) = 5 – 3 = 2 Tap A and C together take to fill 25% part of the tank in, => (25/100) × (48/2) = 6 hours
Which of the following tissue has primary function of supporting the plant organs?Â
In plant, the cell walls of ___ cells are coagulated with the deposition of suberin which makes them impervious to water and air.Â
The precursor of auxin is _____
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Which of the following element has a perforated cell wall?
In the conditions of severe drought, the release of ___ plant hormone starts which closes the plant stomata.
Site for protein synthesis is _______
The enzyme synthesises the complementary DNA strand of the desired gene from its mRNA is?
Cut or excised leaves remain green for long if induced to root or dipped in_____
