Question
In bucket A and B, the quantity of mixture are (3z-25)
litre and (5z+25) litre respectively. If (y-15) and (y+60) litres of water is mixed in bucket A and B respectively, then in each bucket the quantity of milk will be 20% more than the quantity of water. In each bucket the initial quality of milk is three times of the initial quantity of water. Find out the value of ‘z’.Solution
 [(3/4)x(3z-25)] /[(1/4)x(3z-25)+(y-15)] = 120/100 By solving the above expression. 24y = 27z+135  Eq.(i) [(3/4)x(5z+25)] /[(1/4)x(5z+25)+(y+60)] = 120/100 By solving the above expression. 24y = 45z−1215  Eq.(ii) So Eq.(i) = Eq.(ii). 27z+135 = 45z-1215 45z-27z = 1215+135 18z = 1350 value of ‘z’ = 75
625 × (?% ÷ 125) = 250% of 10
What will come in place of (?) in the given expression.
{(60% of 250) + √144} ÷ (3² - 4) = ?What will come in the place of question mark (?) in the given expression?
(30 × 5 + 20) × 2 = ?
Determine the simplified value of the expression: 12 × 15 - 20 + 15 + 12 - 18 + 3 × 4 + 18.
- Find the value of the expression:
40 + 5 – 7 × [16 + 9 – 3 × (27 – 13)] - What will come in the place of question mark (?) in the given expression?
(√1089 + 47) X 4.5 = ? - √256 X 10 2048 × 1824 ÷ 76 = (? - 212) × 64
- What will come in the place of question mark (?) in the given expression?
(198/13) X (52/11) - ? ÷ 5 = 13 + 68 ÷ 4 Train M, ‘x’ metres long crosses (x – 30) metres long platform in 22 seconds while train N having the length (x + 30) metres crosses the same plat...
30% of 600 –