Question
In bucket A and B, the quantity of mixture are (3z-25)
litre and (5z+25) litre respectively. If (y-15) and (y+60) litres of water is mixed in bucket A and B respectively, then in each bucket the quantity of milk will be 20% more than the quantity of water. In each bucket the initial quality of milk is three times of the initial quantity of water. Find out the value of ‘z’.Solution
 [(3/4)x(3z-25)] /[(1/4)x(3z-25)+(y-15)] = 120/100 By solving the above expression. 24y = 27z+135  Eq.(i) [(3/4)x(5z+25)] /[(1/4)x(5z+25)+(y+60)] = 120/100 By solving the above expression. 24y = 45z−1215  Eq.(ii) So Eq.(i) = Eq.(ii). 27z+135 = 45z-1215 45z-27z = 1215+135 18z = 1350 value of ‘z’ = 75
721 +21 x 9 - 118 = ? + 82
The value of ((0.27)2-(0.13)2) / (0.27 + 0.13) is:
√4761 ÷ 23 + √12769 = ? × 58
What value should come in place of the question mark (?) in the following question?
45 × 2 + 180 ÷ 6 − 12 = ? Â
Simplify the following expressions and choose the correct option.
[(7/8 of 256) ÷ 4] + (3/5 of 150) = ?
? × 5.5 = √1225 + 40% of 30% of 37.5% of 5000 – 63
(√ 196 x √ 36 x √ 100) = ?% of 200
- Determine the simplified value of the given expression.
(-6) × {21 – (–3) × (–6)} 30% of 2200 +’?’ x 50 – 1020 = 11x 306 + (√ 2250 ÷ 0.1) Â
Solve the following:
1500 ÷ (9 × 18 ÷ 6 × 3 – 45) ²
