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Let the capacity of the tank be 120 litres {LCM (30 and 40)} Efficiency of pipe ‘A’ = 120 ÷ 30 = 4 litres/hour Efficiency of leak ‘A’ = 120 ÷ 40 = 3 litres/hour Combined efficiency of pipe ‘A’ and leak ‘A’ = 4 – 3 = 1 litre/hour Combined efficiency of pipe ‘A’, ‘B’ and leak ‘A’ = 120 ÷ 15 = 8 units/hour Efficiency of pipe ‘B’ = 8 – 1 = 7 units/hour Time taken by pipe ‘B’ and leak ‘A’ to fill the tank = 120 ÷ (7 – 3) = 30 hours
I. 4x2 + 9x - 9 = 0
II. 4y2 - 19y + 12 = 0
I. x − √2401 = 0
II. y2 − 2401 = 0
I. p² - 10p +21 = 0
II. q² + q -12 = 0
Equation 1: x² - 220x + 12100 = 0
Equation 2: y² - 210y + 11025 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the...
What will be the product of smaller roots of both equations.
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 33x² - 186x + 240 = 0
Equation 2: 35y² - 200y + ...
How many values of x and y satisfy the equation 2x + 4y = 8 & 3x + 6y = 10.
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
I. x2 - 17x + 70 = 0
II. y2 - 11y + 28 = 0