Question
Tap ‘A’ and tap ‘B’ can fill a tank in 40 hours
and 36 hours, respectively. If both taps are opened together, then find the time after which tap ‘A’ must be closed so the whole tank can be filled in 18 hours.Solution
Let total capacity of the tank is 360 litres (LCM of 40 and 30) Quantity of water filled by tap ‘A’ in one hour = 360/40 = 9 litres Quantity of water filled by tap ‘B’ in one hour = 360/36 = 10 litres Let tap ‘A’ is closed after ‘x’ hours So, 19 × x + 10 × (18 – x) = 360 Or, 9x = 180 Or, x = 20 hours
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