Question
How many 5-digit numbers can be formed from 1,2,3,4,5,6
if the number is divisible by 4 and digits do not repeat?Solution
ATQ,
Divisible by 4 → last two digits form numbers divisible by 4: 12, 16, 24, 32, 36, 52, 56, 64. 8 valid endings. For each, remaining 3 digits = 4×3×2=24. Total = 8×24 = 192.
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