Question
A school wants to form a committee of 5 students from 6
boys and 4 girls. How many ways can the committee be formed if it must contain at least 3 boys?Solution
Case I: 3 boys and 2 girls:
6C3 × 4C2 = 20 × 6 = 120
Case II: 4 boys and 1 girl:
6C4 × 4C1 = 15 × 4 = 60
Case III: 5 boys and 0 girls:
6C5 × 4C0 = 6 × 1 = 6
Total = 120 + 60 + 6 = 186 ways
More Permutation and combination Questions
960.02 of 238.89 ÷ 144.01 of 79.97 = ?
620.15 + 1279.98 + ? × (4.79)2 = 149.95% of 1600.14
(8.86)² × (15.01)² ÷ √624.99 = 9?
(√4623.9 + √484.2) – √2303.97 ÷ √1296.4 × √35.98 ÷ √15.99 = ?
?% of 309.99 = 40.01% of 249.99 + 295.98% of 49.99
? + 539.76 ÷ 5.4 × 94.80 = 9829.54
1314.04 – 450.18 + 359.98 ÷ 12.06 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What will be the approximate value of the following questions.
6.992 + (2.01 × 2.98) + ? = 175.03
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