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ATQ, Let the son's present age = x, and the father's present age = y. 14 years ago: Father = 3 × Son = y−14 = 3(x−14) ⟹ y = 3x−28 Now: Father = 2 × Son = y = 2x On Solving we get: From y=2x and y=3x−28: 2x=3x−28⟹x=28 y=2x=56. Sum of ages = x + y = 28+56 = 84 years
The expression of (cot θ + cosec θ −1) / (cot θ − cosec θ+1) is equal to
Which is the largest six digit number, which when divided by 12, 15, 20, 24 and 30, leaves the remainders 8, 11, 16, 20 and 26 respectively.
If a + b2 + c2 = 16, x2 + y2 + z2 = 25 and ax + by + cz = 20, then the value of (a+b+c)/(x+y+z)
If a3 = 117 + b3 and a = 3 + b, then the value of a + b is:
If sec θ + tan θ = m(> 1), then the value of sin θ is (0° < θ < 90°)
The value of the expression (1 + sec22° + cot68°)(1 – cosec22° + tan68°) is
Find x, given 5 (√5)x+6 = (√5)2x+7 :
IfX = (√5 + 1) / (√5 – 1) and y = (√5 – 1) / (√5 + 1) then the value of(x 2+xy+y
If x4 + 2x3 + ax2 + bx + 9 is a perfect square, where a and b are positive real numbers, then the value of a and b are
If a + b + c = 0 then the value of (1/(a+b)(b+c)) + (1/(b+c)(c+a)) + (1/(c+a)(a+b)) is
