Question
14 years ago, the age of a father was three times the
age of his son. Now, the father is twice as old as his son. What is the sum of the present ages of the father and the son?Solution
ATQ, Let the son's present age = x, and the father's present age = y. 14 years ago: Father = 3 × Son = y−14 = 3(x−14) ⟹ y = 3x−28 Now: Father = 2 × Son = y = 2x On Solving we get: From y=2x and y=3x−28: 2x=3x−28⟹x=28 y=2x=56. Sum of ages = x + y = 28+56 = 84 years
0.15, 3.15, 12.30 , 45.90, 195.60, 998
1320, 1352, 1390, 1436, 1488, 1548
213, 215, 225, 257, 313, 393
Find the wrong number in the given number series.
24, 47, 76, 107, 144, 189
Find the wrong number in the given number series.
976, 720, 495, 297, 130, - 14Â
124, 132, 118, 140, 108, 148
- Find the wrong number, in the given number series.
1, 8, 27, 65, 125, 216 112, 222, 440, 872, 1717 , 3424
Find the wrong number in the given number series.
24, 120, 721, 5040, 40320, 362880
In each of the following giving number series, a wrong number is given. Find out the wrong number?
3023, 3132, 3246, 3356, 3471
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