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    Question

    Five toys out of which 2 are identical robots and the

    rest are different action figures are to be arranged in a row. Find the number of arrangements in which the two robots are not placed together.
    A 84 Correct Answer Incorrect Answer
    B 96 Correct Answer Incorrect Answer
    C 36 Correct Answer Incorrect Answer
    D 60 Correct Answer Incorrect Answer
    E 108 Correct Answer Incorrect Answer

    Solution

    Total number of arrangements = 5! = 120 ways
    If we treat the 2 robots as one group, arrangements among themselves = 2! = 2 ways Total arrangements = 120/2 =  60 ways
    Number of arrangements of remaining 4 items = 4! = 24 ways
    Therefore, required number of ways = 60 – 24 = 36 ways

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