Question
In how many ways can a committee of 3 men and 2 women be
formed from 5 men and 6 women?Solution
The number of ways to select 3 men from 5 men = C(5, 3) = 5! / (3!(5-3)!) = (5 × 4 × 3) / (3 × 2 × 1) = 10. The number of ways to select 2 women from 6 women = C(6, 2) = 6! / (2!(6-2)!) = (6 × 5) / (2 × 1) = 15. Total number of ways = 10 × 15 = 150. Correct answer: a. 150
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