Question
In how many ways can a committee of 3 men and 2 women be
formed from 5 men and 6 women?Solution
The number of ways to select 3 men from 5 men = C(5, 3) = 5! / (3!(5-3)!) = (5 × 4 × 3) / (3 × 2 × 1) = 10. The number of ways to select 2 women from 6 women = C(6, 2) = 6! / (2!(6-2)!) = (6 × 5) / (2 × 1) = 15. Total number of ways = 10 × 15 = 150. Correct answer: a. 150
84, 97, ?, 162, 214, 279
In each of the following number series, one term is missing. Find the missing term.
4, 9, 16, 25, 36, ?
71, 79, 88, 152, ?, 393
What will come in place of (?) question mark in the given number series.
12, 27, 44, 65, ?, 139
4    11     22     ?      56    79    106
...- What will come in place of the question mark (?) in the following series?
1, 9, 35, 91, 189, ? 15.5, 62, 186, ?, 2232, 8928
600 Â Â Â 60Â Â Â 12Â Â Â ? Â Â Â Â 1.44Â Â Â Â 0.72
9    14    38    129    ?   2705   16260
...In each of the following series, one term is missing. Find the missing term.
2, 5, 11, 23, 47, ?
Relevant for Exams:
