Question
The population of a town in 2019 was (x + 9000). It
increased by 10% in the first year and by 30% in the second year. The population of the town in 2021 became (x + 15450). Find the population of the town if instead it had increased by 20% in the first year and then decreased by 10% in the second year.Solution
ATQ, (x + 9000) * 110/100 * 130/100 = x + 15450 (x + 9000) * 1.43 = x + 15450 1.43x + 12870 = x + 15450 1.43x – x = 15450 – 12870 0.43x = 2580 x = 6000 Initial population in 2019 = x + 9000 = 6000 + 9000 = 15000 Now, if population had increased by 20% in the first year and decreased by 10% in the second year: New population = (6000 + 9000) * 120/100 * 90/100 = 15000 * 1.2 * 0.9 = 15000 * 1.08 = 16200 So, the new population of the town = 16200
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