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    Question

    In an examination, a student who scores 20% of the

    maximum marks fails by 30 marks. Another student who scores 32% of the maximum marks gets 18 marks more than the pass marks. Find the maximum marks and the pass marks.
    A 400 and 110 Correct Answer Incorrect Answer
    B 320 and 100 Correct Answer Incorrect Answer
    C 465 and 250 Correct Answer Incorrect Answer
    D 325 and 185 Correct Answer Incorrect Answer

    Solution

    Let maximum marks = M Let pass marks = P First student: 20% of M = P − 30 0.20M = P − 30 …(1) Second student: 32% of M = P + 18 0.32M = P + 18 …(2) Subtract (1) from (2): 0.32M − 0.20M = (P + 18) − (P − 30) 0.12M = 48 M = 48 / 0.12 = 400 Now from (1): 0.20 × 400 = P − 30 80 = P − 30 P = 110 Answer: Maximum marks = 400, Pass marks = 110.

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