Question
20% of βxβ and 40% of βyβ together make 138. If
βyβ is 36 more than βxβ, then find the value of (2x β y).Solution
ATQ,
Given: 0.2x+0.4y = 138 y = x+36 Substitute: 0.2x+0.4(x+36) = 138 β 0.2x+0.4x+14.4 = 138 β 0.6x = 123.6 βx = 206 β y = x + 36 = 242 So, 2xβy = 2x β y = 2(206)β242 = 412 β 242 = 170
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