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Let the maximum marks = 100x
Passing marks = 45x
M’s score = (45x)(1 – 0.15) = 38.25x
N’s score = (38.25x)(1 – 0.18) = 31.36x
Sum of the scores of ‘M’ and ‘N’ = 38.25x + 31.36x = 69.61x
Required percentage = {(69.61x – 45x)/69.61x} × 100 = 35.33%
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