Question
In an internal assessment, the minimum passing percentage
is 45%. Marks scored by ‘M’ are 15% less than passing marks, and ‘N’ scores 18% marks less than M. What percent less (up to 2 decimal places) than the sum of M’s and N’s marks should O obtain to pass the exam at the borderline?Solution
ATQ,
Let the maximum marks = 100x
Passing marks = 45x
M’s score = (45x)(1 – 0.15) = 38.25x
N’s score = (38.25x)(1 – 0.18) = 31.36x
Sum of the scores of ‘M’ and ‘N’ = 38.25x + 31.36x = 69.61x
Required percentage = {(69.61x – 45x)/69.61x} × 100 = 35.33%
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