Question
In a university examination, the passing marks are set at
50%. Marks obtained by ‘X’ are 12% less than the passing marks, and ‘Y’ scores 30% marks less than X. What percent less (up to 2 decimal places) than the sum of X’s and Y’s marks should Z obtain to pass the exam at the borderline?Solution
ATQ,
Let the maximum marks = 100x
Passing marks = 50x
X’s score = (50x)(1 – 0.12) = 44x
Y’s score = (44x)(1 – 0.30) = 30.8x
Sum of the scores of ‘X’ and ‘Y’ = 44x + 30.8x = 74.8x
Required percentage = {(74.8x – 50x)/74.8x} × 100 = 33.16%
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