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Let the maximum marks = 100x
Passing marks = 40x
A’s score = (40x)(1 – 0.10) = 36x
B’s score = (36x)(1 – 0.20) = 28.8x
Sum of the scores of ‘A’ and ‘B’ = 36x + 28.8x = 64.8x
Required percentage = {(64.8x – 40x)/64.8x} × 100 = 38.27%
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