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Let, the income of 'A' be Rs. '20x'. So, the income of 'B' = 1.15 X 20x = Rs. '23x' Let, the expenditure of 'A' and 'B' be Rs. '5y' and Rs. '6y', respectively. According to the question, 20x - 5y = 23x - 6y + 100 Or, y - 3x = 100 ....(i) Also, 20x - 6y = 1000 Or, 10x - 3y = 500 ....(ii) Multiple equation (i) with 3 and add it with equation (ii) , we get, 10x - 3y + 3y - 9x = 500 + 300 Or, x = 800 So, the income of 'B' = 20x = 20 X 800 = Rs. 16,000 Hence, option d.
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