Question
In a quiz, Leena scored 45 marks less than Neha. Neha
scored 32 more marks than Omar. Jai scored 95 marks which is 30 marks more than Leena. Ritu’s score is 20 less than the maximum marks of the test. Karan, who scored 22 marks less than Omar in the first test which was of 150 marks, has to get an average score of at least 60% in two tests. If the second test carrying 180 marks, what percentage of marks should he score in the second test to get the overall average score?(Calculate approximate value)Solution
ATQ, Leena’s score = Jai's score - 30 = 95 - 30 = 65 Neha’s score = Leena's score + 45 = 65 + 45 = 110 Omar’s score = Neha's score - 32 = 110 - 32 = 78 Karan’s score in the first test = Omar's score - 22 = 78 - 22 = 56 Total maximum marks of tests = 150 + 180 = 330 Karan has to score 60% of 330 = 330 × (60/100) = 198 marks Remaining required marks = 198 - 56 = 142 Required % = (142/180) × 100 = 78.8889% or 79%
(18.31)2 – (13.68)2 + (2344.20 + 82.32) ÷ ? = 229.90
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
24.01 X 24.99 - ?% of 599.96 = 14.92 X 8.12
20.11 × 6.98 + 21.03 × 6.12 – 37.95 + 92.9 × 5.02 =?
Direction: Solve the following expression and calculate the approximate value.
(5.78 + 3.12)² + 8.2² + 2 × 8.1 × (5.9 + 3.2)
...Find the approximate value of Question mark(?). No need to find the exact value.
(55.96 × 4.01) ÷ 7 + √(120.81) × 3 – 10% of 199.99 = ?<...
888.191 + 2.0001 X 7.961= ?
80.09 * √144.05+ ? * √224.87 = (2109.09 ÷ √1368.79) * 19.89
- 44.83% of 799.88 + (84.12 X 14.98 ÷ 62.87) = ?² + 55.65
The greatest number that will divide 398,436, and 542 leaving 7, 11, and 15 as remainders, respectively, is: