Question
In an examination, Maya scored 42 marks less than Priya.
Priya scored 30 more marks than Rohit. Neel scored 90 marks which is 25 marks more than Maya. Tanvi’s score is 22 less than the maximum marks of the test. Vikram, who scored 18 marks less than Rohit in the first test which was of 130 marks, has to get an average score of at least 65% in two tests. If the second test carrying 160 marks, what percentage of marks should he score in the second test to get the overall average score? (Calculate approximate value)Solution
ATQ, Maya’s score = Neel's score - 25 = 90 - 25 = 65 Priya’s score = Maya's score + 42 = 65 + 42 = 107 Rohit’s score = Priya's score - 30 = 107 - 30 = 77 Vikram’s score in the first test = Rohit's score - 18 = 77 - 18 = 59 Total maximum marks of tests = 130 + 160 = 290 Vikram has to score 65% of 290 = 290 × (65/100) = 188.5 marks Remaining required marks = 188.5 - 59 = 129.5 Required % = (129.5/160) × 100 = 80.9375% or 81%
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