Question
The cost price of juice is 50% more than the cost price
of lemon soda. A juice seller mixed 120 ml of juice with 30 ml of lemon soda in a glass. By mistake, 50 ml of the mixture from the glass is spilled out, and to recover the loss, he added 30 ml of lemon soda back into the glass. He sold the entire mixture from the glass at a rate 60% higher than the cost price of the juice. Find his profit/loss percentage in this transaction.Solution
ATQ, Let the cost price of 1 ml Lemon soda be Rs. ‘m’. So, the cost price of 1 ml juice = Rs. 1.5m Cost price of the whole content juice seller had = 120 × 1.5m + (30 + 30) × m = Rs. 240m Total quantity of mixture sold = 120 + 30 – 50 + 30 = 130ml Selling price of 1 ml mixture = 1.6 × 1.5m = Rs. 2.4m So, the selling price of the whole mixture sold by him = 130 × 2.4m = Rs. 312m So, the profit percent = {(312m – 240m)/240m} × 100 = 30%
(1177.99 + 226.99 + 94.923) ÷ 24.97% of 59.989 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(20.23% of 780.31) + ? + (29.87% of 89.87) = 283
((341.789)1/3 × (0.0049)1/2)× 429.798/6.88 =?
- 248.95 of 21.33 - 134.56 of 15.77 = ? of 14.04 of 22.45
{(22.22 2 + 6.06 3 ) ÷ 15.15} × 3.03 = ? – 55.05 × 4.04
630.11 ÷ 20.98 × 5.14 – 125.9 = √?Â
(2310.23 ÷ 32.98) + (1008.32 ÷ 23.9) + 1594.11 = ?
? = 25.08 + 11.99 × 24.07
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