Ratio of males to females in city A is 2:3 and ratio of males to females in city B is 14:25. Number of males in city B are (x+10)% more than number of males in city
A. Number of females in city B are 66(2/3)% more than number of females in city A and difference between them is 300. Find (x + 20)% of total population of city A?

Let, number of females in city A = 3a So, number of females in city B = (1+2/3) of 3a = 5/3× 3a = 5a 5a – 3a = 300(given) 2a = 300 a = 150 So, number of females in city A = 3a = 450 Number of females in city B = 750 So, according to the question, Number of males in city A = 300 Number of males in city B = 420 Number of males in city B are (x + 10)% more than number of males in city A =    (x + 10)% = 40% x = 30% Total population of city A = 450 + 300 = 750 (x + 20)% = 50% So, (x + 20)% of total population of city A = 50% of Total population of city A = Hence, option B is the correct answer.