Question
A man donated 13%, 14% and 22% of his income to three
NGOs ‘A’, ‘B’ and ‘C’, respectively. They spent 75%, 80% and 50% of respective sums received by them. If total sum left with three NGOs is Rs. 1705, then find the income of man.Solution
Let the income of the man be Rs. x Therefore, sum donated to NGO ‘A’ = Rs. 0.13x Sum left with NGO ‘A’ = 0.25 × 0.13x = Rs. 0.0325x Sum donated to NGO ‘B’ = Rs. 0.14x Sum left with NGO ‘B’ = 0.2 × 0.14x = Rs. 0.028x Sum donated to NGO ‘C’ = Rs. 0.22x Sum left with NGO ‘C’ = 0.5 × 0.22x = Rs. 0.11x According to the question, 0.0325x + 0.028x + 0.11x = 1705 Or, 0.1705x = 1705 Or, x = 1705/0.1705 = 10000 Therefore, income of man = Rs. 10000
182 + 10 × 12 - ? = 312
53 – 8 = ? + 126
2850 ÷ 2.5 - ? × 42 = 300
Determine the value of ‘x’ if x% of 500 plus {1250 ÷ x of 10} × 5 equals 130
Evaluate
32 ÷ 2 of 7 of [14 ÷ 7 of (6 ÷ 3 + 5)] + (6 ÷ 2 + 1)
What will come in place of (?) in the given expression.
[(24 ÷ 3) + (18 × 2)] - 5 = ?666(2/3)% of 30 - 116(2/3)% of 90 =?
√ [? x 11 + (√ 1296)] = 16
What will come in the place of question mark (?) in the given expression?
{122 + (66/4) + (252/8)} ÷ 8 = (?)1/2
(62 + 82 ) X ? = 80% of 500 - 25 X 4
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