πŸ“’ Too many exams? Don’t know which one suits you best? Book Your Free Expert πŸ‘‰ call Now!


    Question

    The sum of the monthly incomes of β€˜A’, β€˜B’ and

    β€˜C’ is Rs. 95000 which is 4 times the monthly income of β€˜C’. If β€˜A’ spends 25% of his income while β€˜B’ spends 80% of his income and the sum of their savings is Rs. 18900, then find the savings of β€˜A’.
    A 6,340.91 Correct Answer Incorrect Answer
    B 2400.65 Correct Answer Incorrect Answer
    C 2625.55 Correct Answer Incorrect Answer
    D 3075.33 Correct Answer Incorrect Answer

    Solution

    Given:- A+B+C=95,000 A+B+C=4C, So A+B=3C A's savings = 75% of B's savings = 20% of B, and their combined savings = Rs. 18,900. Therefore, A+B+C=4C, we find C=23,750. Substitute C=23,750 into A+B=3C, So A+B=71,250. Use the savings equation 0.75A+0.20B=18,900, and substitute B=71,250βˆ’A. Solve the system of equations to get A=8,454.55. Hence, Savings of A's savings = 75% of A = 0.75Γ—8,454.55 = 6,340.91.

    Practice Next
    ask-question