Question
The sum of the monthly incomes of βAβ, βBβ and
βCβ is Rs. 60000 which is 4 times the monthly income of βCβ. If βAβ spends 60% of his income while βBβ spends 80% of his income and the sum of their savings is Rs. 16000, then find the savings of βAβ.Solution
Monthly income of βCβ = 60000/4 = Rs. 15000 Let the monthly income of βAβ be Rs. x Therefore, monthly income of βBβ = Rs. (45000 β x) According to the question, 0.40x + 0.20(45000 β x) = 16000 Or, 0.2x = 7000 x = 35000 Or, savings of βAβ = 0.4x = Rs. 14000
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