Question
The total strength of school A is 40% more than that of
school B. In school A and B, out of total number of students, 10% and 30% respectively are girls. The number of boys in school A is how much percent more/less than that in school B?Solution
Let the total number of students in school B be ‘x’. Therefore, total number of students in school A = 1.4x Number of boys in school A = 0.90 × 1.4x = 1.26x Number of boys in school B = 0.7x Required % = [(1.26x – 0.7x)/0.7x] × 100 = 80%
In the question, three series I, II and III are given. Find the value of x, y and z to establish the correct relation among them and choose the correct...
1156Â Â Â Â Â Â Â 372Â Â Â Â Â Â Â Â Â 997Â Â Â Â Â Â Â Â Â 513Â Â Â Â Â Â Â Â Â 874Â Â Â Â Â Â Â Â Â 618
1936     a        �...
If  2  4  6  x  14  28  30
Then, x³+ 2 x+1 = ?
20 25 54 165 662 ?
...Study the given pattern carefully and select the number that can replace the question mark (?) in it.
4 7 6
15 ? 21
44 68 60
35.25 71 146 296 624 1376
...62 123 214 341 ? 727
...12, 23, 68, 271, 1354, ?
6 6 3 6.5 12 33
...2 5 16 65 326 ?
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